Could you explain the "No, the reason is you put 680v square waves into the equipment, with 1200v spikes on top of it!" 480V 60Hz is the system supply voltage. The output of the VFD is 400V 50 Hz. The voltage supplied to the HVAC Units is 400V 50 Hz. 480V 60 Hz is only up to the AC panel/VFD. there is no issue with the VFDs. 3 hp (2.2 kW) VFD, Three Phase 220V, 380V, 480V. $280.48. SKU: GK3000-4T0022G. Low cost 3 hp (2.2 kW) VFD, three phase 220V, 380V, 480V variable frequency drive, IP20 enclosure, RS485 enabled, V/F & vector control, brand new direct sale by manufacturer. Quick View. Add to cart. 5254.9. 3853.6. 843.0. 613.1. 486.3. A KW and KVa amperage chart will help you choose the right generator size for your application. This guide will show you the amperage at each voltage and KW we offer at Affordable Generator. There are devices called "boost converters" that can step up your voltage. They are used extensively in the small VFDs that accept 120V single phase input and allow you to run a 230V 3 phase motor. In the Chinese unit you linked to, they are using the same technique to boost 220V single phase to 380V 3 phase. But The drive will accept 380V, no problem. But the output voltage will be limited by that as well, standard VFDs cannot provide an output voltage that is greater than the input voltage. So if your motor is designed for 480V, you will end up with a limited speed or a loss of torque. I would agree it will probably be fine. It may be that the manufacturer produces motors for 400V, 415V and 440V (the three common voltages in that region) and has a single production line for all three, in which case the motor will be exactly the same as a 415V motor. Can I run a 380V motor on 480V? Can you run a 380V motor on 480V? The drive If you use this formula you will find that using 480 V as to using 380V to power the motors will just increase to motor torque. Running a 380-volt motor at 480-volt most likely will not burn the motors up. I have done this a couple times and the motor ran just fine. It will depend on the condition of the 380 volt motors and what they are driving. When you don’t give a motor full voltage, it produces less torque, less at the square of the voltage reduction. So 480/575 = roughly 83%, so your peak torque capability will be reduced to about 70% of normal. Since synchronous speed remains the same, you HP becomes 70% as well. If your motor was over sized by 30% or more it will be fine. For Example: Given a 480V to 208V Delta > Wye, with an input voltage of 460V and a tap set for 480V would yield: (460/480) X 208 = 199.33V. In order to yield 208V this tap setting would be insufficient. You would have to use a tap setting that was lower, such as 456V. The formula to convert amps to kilowatts for three-phase AC circuits where the line-to-neutral RMS voltage is known is: P (kW) = I (A) × V L-N (V) × PF × 3 1,000. Thus, the power P in kilowatts is equal to the product of the current I in amps, the line-to-neutral voltage V in volts, and the power factor PF, multiplied by 3, then divided by YXV9r.